class LLNode:
    '''Node to be used in linked list

    nxt: LLNode -- next node
                   None iff we're at end of list
    value: object --- data for current node
    '''

    def __init__(self, value, nxt=None):
        ''' (LLNode, object, LLNode) -> NoneType

        Create LLNode (self) with data value and successor nxt.
        '''
        self.value, self.nxt = value, nxt

    def __repr__(self):
        ''' (LLNode) -> str

        Return a string representation of LLNode (self) that can yields
        an equivalent LLNode if evaluated in Python.

        >>> n = LLNode(5, LLNode(7))
        >>> n.nxt
        LLNode(7)
        >>> n
        LLNode(5, LLNode(7))
        '''
        if self.nxt is None:
            return 'LLNode({})'.format(repr(self.value))
        else:
            return 'LLNode({}, {})'.format(repr(self.value), repr(self.nxt))

    def __str__(self):
        ''' (LLNode) -> str

        Return a user-friendly representation of this LLNode.

        >>> n = LLNode(5, LLNode(7))
        >>> print(n)
        5 -> 7 ->|
        '''
        if self.nxt is None:
            return '{} ->|'.format(str(self.value))
        else:
            return '{} -> {}'.format(str(self.value), str(self.nxt))

    def __eq__(self, other):
        ''' (LLNode, object) -> bool

        Return whether LLNode (self) is equivalent to other.

        >>> LLNode(5).__eq__(5)
        False
        >>> n = LLNode(5, LLNode(7))
        >>> n2 = LLNode(5, LLNode(7, None))
        >>> n.__eq__(n2)
        True
        '''
        return (type(self) == type(other) and
                (self.value, self.nxt) == (other.value, other.nxt))



class LinkedList:
    '''Collection of LLNodes

    front: LLNode -- front of list
    back:  LLNode -- back of list'''

    def __init__(self):
        ''' (LinkedList) -> NoneType

        Create an empty linked list.
        '''
        self.front, self.back = None, None
        self.size = 0

    def __str__(self):
        ''' (LinkedList) -> str

        Return a human-friendly string representation of
        LinkedList (self)

        >>> lnk = LinkedList()
        >>> lnk.prepend(5)
        >>> print(lnk)
        5 ->|
        '''
        return str(self.front)

    def __eq__(self, other):
        ''' (LinkedList, object) -> bool

        Return whether LinkedList (self) is equivalent to
        other.

        >>> LinkedList().__eq__(None)
        False
        >>> lnk = LinkedList()
        >>> lnk.prepend(5)
        >>> lnk2 = LinkedList()
        >>> lnk2.prepend(5)
        >>> lnk.__eq__(lnk2)
        True
        '''
        return (type(self) == type(other) and
                (self.size, self.front, self.back) == (other.size, other.front, other.back))

    def append(self, value):
        ''' (LinkedList, object) -> NoneType

        Insert a new node with value at back of lnk.

        >>> lnk = LinkedList()
        >>> lnk.append(5)
        >>> lnk.size
        1
        >>> print(lnk.front)
        5 ->|
        >>> lnk.append(6)
        >>> lnk.size
        2
        >>> print(lnk.front)
        5 -> 6 ->|
        '''
        new_node = LLNode(value)
        if self.front is None:
            self.front = self.back = new_node
        else:
            assert self.back, 'Unexpected None node'
            self.back.nxt = new_node
            self.back = new_node
        self.size += 1

    def prepend(self, value):
        ''' (LinkedList, object) -> Nonetype

        Insert value at front of LLNode (self).

        >>> lnk = LinkedList()
        >>> lnk.prepend(0)
        >>> lnk.prepend(1)
        >>> lnk.prepend(2)
        >>> str(lnk.front)
        '2 -> 1 -> 0 ->|'
        >>> lnk.size
        3
        '''
        self.front = LLNode(value, self.front)
        if self.back is None:
            self.back = self.front
        self.size += 1

    def delete_front(self):
        ''' (LinkedList) -> NoneType

        Delete front node from LinkedList (self).

        Assume self.front is not None

        >>> lnk = LinkedList()
        >>> lnk.prepend(0)
        >>> lnk.prepend(1)
        >>> lnk.prepend(2)
        >>> lnk.delete_front()
        >>> str(lnk.front)
        '1 -> 0 ->|'
        >>> lnk.size
        2
        >>> lnk.delete_front()
        >>> lnk.delete_front()
        >>> str(lnk.front)
        'None'
        '''
        if self.back == self.front:
            self.back = None
        self.front = self.front.nxt
        self.size -= 1

    def __getitem__(self, index):
        ''' (LinkedList, int|slice) -> object

        Return the value at index.
        # Don't worry about slices for now

        >>> lnk = LinkedList()
        >>> lnk.prepend(1)
        >>> lnk.prepend(0)
        >>> lnk.__getitem__(1)
        1
        >>> lnk[-1]
        1
        '''
        if index >= self.size or self.size == 0:
            return IndexError('too big!!!')
        elif index < 0:
            return self.__getitem__(self.size + index)
        else:
            cur_node = self.front
            for step in range(0, index):
                cur_node = cur_node.nxt
                assert cur_node,\
                       'step: {}, out of range'.format(step)
            return cur_node.value

    def __contains__(self, value):
        ''' (LinkedList, object) -> bool

        Return whether LinkedList (self) contains value.

        >>> lnk = LinkedList()
        >>> lnk.prepend(0)
        >>> lnk.prepend(1)
        >>> lnk.prepend(2)
        >>> lnk.__contains__(1)
        True
        >>> lnk.__contains__(3)
        False
        '''
        cur_node = self.front
        while cur_node:
            if cur_node.value == value:
                return True
            cur_node = cur_node.nxt
        return False


if __name__ == '__main__':
    import doctest
    doctest.testmod()